[Merged by Bors] - feat(Analysis/SpecialFunctions/Complex/Log): natural number versions of exp_eq_one_iff#38015
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…f exp_eq_one_iff Add `Complex.exp_eq_one_iff_of_im_nonneg`, a variant of `Complex.exp_eq_one_iff` that produces a natural number instead of an integer, under the hypothesis that the imaginary part is nonneg. Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
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…ff N divides k Add `Complex.exp_two_pi_mul_I_mul_div_eq_one_iff`: for natural numbers `k` and `N` with `N ≠ 0`, `exp (2 * π * I * k / N) = 1 ↔ N ∣ k`. Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
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Co-authored-by: Jireh Loreaux <loreaujy@gmail.com>
Co-authored-by: Jireh Loreaux <loreaujy@gmail.com>
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…of exp_eq_one_iff (#38015) Add two lemmas: - `Complex.exp_eq_one_iff_of_im_nonneg`, a variant of `Complex.exp_eq_one_iff` that gives a natural number instead of an integer, under the hypothesis that the imaginary part is nonneg. - `Complex.exp_two_pi_mul_I_mul_div_eq_one_iff`, showing that `exp (2πik/N) = 1` if and only if `N ∣ k`. 🤖 Generated with [Claude Code](https://claude.com/claude-code)
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Add two lemmas:
Complex.exp_eq_one_iff_of_im_nonneg, a variant ofComplex.exp_eq_one_iffthat gives a natural number instead of an integer, under the hypothesis that the imaginary part is nonneg.Complex.exp_two_pi_mul_I_mul_div_eq_one_iff, showing thatexp (2πik/N) = 1if and only ifN ∣ k.🤖 Generated with Claude Code